SOLUTION: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?

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 Question 401228: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together? Found 3 solutions by Tatiana_Stebko, dmf30633, Alan3354:Answer by Tatiana_Stebko(1326)   (Show Source): You can put this solution on YOUR website!Sally can paint a house in 4 hours, so in 1 hour she paints part of the house John can paint the same house in 6 hour, so in 1 hour he paints part of the house If they work together T hours, then Sally will paint part of house and John part of house, together they paint / In this case they will paint all house, so T=2 2/5 hour T=2hours 24min Sally and John need for paint all house together Answer by dmf30633(3)   (Show Source): You can put this solution on YOUR website!If sally paints one house in 4 hours =1/4 and John can paint one in 6 hours = 1/6, how long would it take for both to paint one house. First lets add our workers together. 1/4 + 1/6 finding the lowest common multiple at 12 we then 3*(1/4) + 2*(1/6) resulting in 3/12 + 2/12 or 5/12 so we now know together sally and john can paint 5 houses in 12 hours to find out how long it takes to do one, we simply divide 12 by 5 _2.4_____ 5/12 10 20 20 0 It would take 2.4 hours to paint the house together. Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!Use the shortcut, same time = product/sum = 4*6/(4 + 6) = 24/10 = 2.4 hours