SOLUTION: 1 number is twice another number, if the sum of their reciprocal is 1/4 find the 2 numbers

Question 324261: 1 number is twice another number, if the sum of their reciprocal is 1/4 find the 2 numbers
Found 2 solutions by unlockmath, MathTherapy:
Answer by unlockmath(1688) (Show Source): You can put this solution on YOUR website!
Hello,
Let's have x & y represent the two numbers.
The equations will be:
y=2x
1/y + 1/2x = 1/4
Replace y with 2x to get:
1/2x + 1/2x = 1/4
Combine terms to get:
2/2x=1/4
Multiply each side by 8x to get:
8=2x
Divide each side by 2:
x=4
y=8
Make sense?
RJ
www.math-unlock.com
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
1 number is twice another number, if the sum of their reciprocal is 1/4 find the 2 numbers

Let the smaller number be S

Then the larger number is 2S, since one number is twice the other

Reciprocal of the smaller number, or S is , and the reciprocal of the larger number is

Since the reciprocals sum to , then we'll have:

Multiplying by LCD, 4S, we have: 4 + 2 = S. So S, or the smaller number is , and the larger number is (6*2).

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Check
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Smaller #: 6 ; Larger #: 12

(TRUE)

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