SOLUTION: Jeff and Diana are working on Math homework. Jeff can comlete 4 math problems in 11 minutes. Diana can complete 7 math problems in 25 minutes. Who is faster?
11/4=25/7
2.75=3.
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Question 262209: Jeff and Diana are working on Math homework. Jeff can comlete 4 math problems in 11 minutes. Diana can complete 7 math problems in 25 minutes. Who is faster?
11/4=25/7
2.75=3.57
Jeff is faster.
Is this right
Found 3 solutions by Theo, Alan3354, palanisamy:
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
jeff completes 4 in 11 minutes
dana completes 7 in 25 minutes.
jeff takes 11/4 = 2.75 minutes to complete 1 problem.
dana takes 25/7 = 3.57 minutes to complete 1 problem.
jeff is faster.
you are correct.
another way of looking at is rate * time = units produced.
with jeff, you get r * 11 = 4
with dana, you get 4 * 25 = 7
jeff's rate is 4/11 = .36 problems per minute.
dana's rate is 7/25 = .28 problems per minute.
jeff's rate per minute is higher than dana's.
jeff is faster.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Jeff and Diana are working on Math homework. Jeff can comlete 4 math problems in 11 minutes. Diana can complete 7 math problems in 25 minutes. Who is faster?
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Faster is the most problems per minute.
4/11 vs 7/25
4/11 = 0.36 problems/min
7/25 = 0.28 problems/min
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Jeff does more problems per minute.
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You can find the common denominator, too
4/11 = 100/275
7/25 = 77/275
100 is more than 77
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The inverse is minutes per problem, then the smaller number is faster.
11/4 = 2.75 mins per problem
25/7 =~ 3.57 mins per problem
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Maybe Jeff did the easy problems.
Answer by palanisamy(496) (Show Source): You can put this solution on YOUR website!
Jeff can complete 4 math problems in 11 minutes
In one minute Jeff can complete 4/11 = 0.3636 part of a problem.
Next, Diana can complete 7 math problems in 25 minutes.
In one minute Diana can complete 7/25 = 0.28 part of a problem.
So Jeff is faster
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