SOLUTION: How much water should be added to 32 ounces of a 30% solution of alcohol to dilute it to a 16% solution? Formula to develop the problem

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Question 255434: How much water should be added to 32 ounces of a 30% solution of alcohol to dilute it to a 16% solution?
Formula to develop the problem
Found 2 solutions by ankor@dixie-net.com, amalm06:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How much water should be added to 32 ounces of a 30% solution of alcohol to dilute it to a 16% solution?
Formula to develop the problem
:
Let x = amt of water
:
.30(32) = .16(32+x)
9.6 = 5.12 + .16x
9.6 - 5.12 = .16x
4.48 = .16x
x = 4.48%2F.16
x = 28 oz of water

Answer by amalm06(224) About Me  (Show Source):
You can put this solution on YOUR website!
Many of the "add water" questions can be solved in one step. It is important to know the longer method, but the shorter method is useful as a check and for standardized exams.

Longer method: (0.30)(32)+ 0= (32+x)(0.16)

Solve for x to get the amount of water.

Shorter method: (14/16)(32)= 28 oz of water (Answer)