SOLUTION: If Sally can paint a house in 4 hours and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together?
The furthest I can get is
Algebra.Com
Question 246801: If Sally can paint a house in 4 hours and John can paint the same house in 6 hours, how long will it take for both of them to paint the house together?
The furthest I can get is the following:
Sally 4 hours/house = John 6 hours/house
I have no idea where to go from here. Any help would be appreciated.
thanks,
Carrie
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use this method to solve all of these sorts of problems. Just plug in your numbers and do the arithmetic.
If A can do a job in x time periods, then A can do 
of the job in 1 time period. Likewise, if B can do the same job in y time periods, then B can do 
of the job in 1 time period.
So, working together, they can do
of the job in 1 time period.
Therefore, they can do the whole job in:
time periods.
John
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