SOLUTION: Solve the following without using cross multiplication:
A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel?
Please help.
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Proportions
-> SOLUTION: Solve the following without using cross multiplication:
A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel?
Please help.
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Question 242526: Solve the following without using cross multiplication:
A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel?
Please help. Even just some ideas would be great. Thank you. Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!
You can set up the proportion the same way, just do the division first. Not that it matters much. You still end up doing the same arithmetic.
The only way to solve it without using some form of the manipulations of cross-multiplication is to not use algebra at all. You go find the motorbike that you know can run 10 minutes on $1.30, put $0.91 worth of gas in the tank that you have previously emptied, and then time how long the bike runs.
