SOLUTION: Solve the following without using cross multiplication: A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel? Please help.

Question 242526: Solve the following without using cross multiplication:
A motorbike can run for 10 minutes on $1.30 worth of fuel. How long could it run on $0.91 worth of fuel?
Please help. Even just some ideas would be great. Thank you.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

You can set up the proportion the same way, just do the division first. Not that it matters much. You still end up doing the same arithmetic.

The only way to solve it without using some form of the manipulations of cross-multiplication is to not use algebra at all. You go find the motorbike that you know can run 10 minutes on $1.30, put $0.91 worth of gas in the tank that you have previously emptied, and then time how long the bike runs.

John

RELATED QUESTIONS
How can I simplify x+1/4= x+3/3 without using cross multiplication? (answered by robertb)

2. Ram is speeding along a highway when he sees a police motorbike parked on the side of (answered by Alan3354)

when a truck travels 60kmph, it uses 30% more fuel to travel any distance than it takes... (answered by ankor@dixie-net.com)

If a generator can run for 6 hours when its fuel tank is 3/5 full, how long can it run... (answered by josgarithmetic,MathTherapy)

You run 3 miles for 30 minutes, so you run 1 mile for 10 minutes. x = minutes you run (answered by Alan3354)

3x --- - 1/3 = 2 2 Use cross-multiplication to solve. How do I get rid of... (answered by rothauserc,Boreal)

Using application of rational expressions? I can run 5 miles in 1 hour. I used to run... (answered by richwmiller,JBarnum)

Hi Please help me answer this hard word problem. An Airplane whose speed in still air... (answered by scott8148)

An engine being tested for fuel consumption was operated at two fixed settings. The first (answered by stanbon)