SOLUTION: The length of the skid mark of an automobile sliding to a stop is directly proportional to the square of the velocity. It was found that a car traveling 60 miles per hour left a s

Question 236956: The length of the skid mark of an automobile sliding to a stop is directly proportional to the square of the velocity. It was found that a car traveling 60 miles per hour left a skid mark 172 feet in length when attempting to stop. Find the length of the skid marks of a car traveling 50 miles per hour.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
Let L= skid length in ft,,,,v= veolcity in MPH
.
L=kv^2
.
subst data given,,,,,172 = k (60)^2,,,,,,,k= 172/60^2 = .0477
.
proportion becomes,,,L= .0477 v^2
.
for v=50,,,,,L = .0477 * 50^2 = 119.44 ft
.
.
checking,,,, 119.44/50^2 = .0477,,,,ok

RELATED QUESTIONS
The distance required for a car to stop is directly proportional to the square of its... (answered by checkley71,chitra)

The distance required for a car to stop is directly proportional to the square of its... (answered by dolly)

x is directly proportional to the square of... (answered by Alan3354)

the relative aperture, or f-stop, of a 23.5-mm diameter lens is directly proportional to... (answered by stanbon)

Investigators at a traffic accident use the equation: D = 0.04v2 + 0.8v where v is the... (answered by stanbon)

Relatively aperture. The relative aperture , or f-stop, of a 23.5mm diameter lens is... (answered by ikleyn)

using the formula s=2sqrt5x (I am having trouble inserting the radical sign so i used... (answered by Theo)

Skid mark analysis is one way to estimate the speed a car was traveling prior to an... (answered by stanbon)

I did the work, but got the question wrong. The distance a car needs to stop is... (answered by rozy101)