SOLUTION: the length of a rectangle is 4ft more than twice the with. The area of the rectangle is 48ft squared. Find the length and width of the rectangle.

Algebra ->  Proportions -> SOLUTION: the length of a rectangle is 4ft more than twice the with. The area of the rectangle is 48ft squared. Find the length and width of the rectangle.      Log On


   



Question 231274: the length of a rectangle is 4ft more than twice the with. The area of the rectangle is 48ft squared. Find the length and width of the rectangle.
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
Area=LW
L=2W+4
48=(2W+4)W
48=2W^2+4W
2W^2+4W-48=0
2(W^2+2W-24)=0
2(W+6)(W-4)=0
W-4=0
W=4 ANS FOR THE WIDTH.
L=2*4+4
L=8+4
L=12 ANS. FOR THE LENGTH.
PROOF:
48=12*4
48=48