# SOLUTION: Respected sir & madum, 1] find the ratio of x:y:z,from the following equation : x-2y+z=0 .....(1) 3x+2y-3z=0....(2) 2]solve the following simultaneous equatins by cro

Algebra ->  Proportions -> SOLUTION: Respected sir & madum, 1] find the ratio of x:y:z,from the following equation : x-2y+z=0 .....(1) 3x+2y-3z=0....(2) 2]solve the following simultaneous equatins by cro      Log On

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 Click here to see ALL problems on Proportions Question 197598: Respected sir & madum, 1] find the ratio of x:y:z,from the following equation : x-2y+z=0 .....(1) 3x+2y-3z=0....(2) 2]solve the following simultaneous equatins by cross multiplication method 5x-3y=1 ..... (1) x+2y=12......(2) plz solve my difficulty as soon an possible...need simple explaination. regards. Binita. Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!1] find the ratio of x:y:z,from the following equations : x-2y+z=0 .....(1) 3x+2y-3z=0....(2) ------------ Find z:x by eliminating "y": Add the two equations to get: 4x - 2z = 0 2z = 4x z = 2x z:x = 2:1 x:z = 1:2 --------------- Now find x:y by eliminating "z": 3x -6y + 3z = 0 3x + 2y - 3z = 0 --- Add to get: 6x -4y = 0 3x = 2y x/y : 2/3 x:y = 2;3 ---------------- x:y:z = ? 2:3:4 ============= 2]solve the following simultaneous equations by cross multiplication method 5x-3y=1 ..... (1) x+2y=12......(2) --------- (5x-3y)/(x+2y) = 1/12 12(5x-3y) = x+2y 60x - 36y = x+2y 59x = 38y x = (38/59)y ----- Substitute to solve for "y" (38/59)y + 2y = 12 (19/59)y + y = 6 (78/59)y = 6 y = 59*6/78 y = 59/13 -------------------- Substitute to solve for "x": x = (38/59)(59/13) x = 38/13 ============================ Cheers, Stan H.