Question 193450: Respected sir,
[1] 94 is divided in to two parts in such a way that the fifth part of the first and the eighth part of the second are in the ratio 3:4,the first part is ?
[2] Rs.1980 are divided among A,B,C so that half of A's part ,one-third of B's part and one-sixth of C's part are equal.Then , B's part is ?
plz solve my ratio ,proportion difficualty .waiting for yur reply.
thank you sir.
Regards.
Binita. Found 2 solutions by solver91311, edjones: Answer by solver91311(12126) (Show Source): Answer by edjones(7311) (Show Source):
You can put this solution on YOUR website!Let f=first part and s=the second
f+s=94
f=94-s
.
.2f/.125s=3/4
.2(94-s)/.125s=3/4
(18.8-.2s)/.125s=3/4
4(18.8-.2s)=3*.125s
75.2-.8s=.375s
1.175s=75.2
s=64
f=30
I'll try to get back to you regarding the 2nd part.
.
Ed
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