SOLUTION: Determine wether the line PQ is parallel or perpendicular or neither to a line with a slope of -2. P(-2,1) Q(6,5) I did the following:y-1=-2(x--2) y-1=-2x-4 y=-2x-3 i got this

Question 162855This question is from textbook beginning and intermidiate algebra
: Determine wether the line PQ is parallel or perpendicular or neither to a line with a slope of -2. P(-2,1) Q(6,5)
I did the following:y-1=-2(x--2)
y-1=-2x-4
y=-2x-3 i got this for p
for Q
y-5=-2(x-6)
y-5=-2x+12
y=-2x+17 so i thought they were parallel; but they are perpendicular i got this one wrong on my test but i do not know what i did wrong please help This question is from textbook beginning and intermidiate algebra

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Note: you don't need to find the equation of the line, you only need the slopes of two lines to figure if they are parallel, perpendicular, or neither

Slope of PQ:

Start with the slope formula.

Plug in , , , and . These values come from the points P(-2,1) and Q(6,5)

Subtract from to get

Subtract from to get

Reduce

So the slope of the line that goes through the points P(-2,1) and Q(6,5) is

Since the product of the given slope -2 and the slope is , this means that the two lines are perpendicular.

Note: you used the same slope twice to get your answer. You forgot to calculate the slope of the line that goes through PQ (see above)
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