Questions on Algebra: Proportions answered by real tutors!

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Question 143055: Find two real numbers that have a sum of 8 and a product of 2.: Find two real numbers that have a sum of 8 and a product of 2.
Answer by checkley77(3639) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=8 or x=8-y
x*y=2
(8-y)*y=2
8y-y^2=2
-y^2+8y-2=0
y^2-8y+2=0
y = (-b +- sqrt( b^2-4*a*c ))/(2*a)
y=(8+-sqrt[-8^2-4*1*2])/2*1
y=(8+-sqrt[64-8])/2
y=(8+-sqrt56)/2
y=(8+-7.48)/2
y=15.48/2
y=7.74 answer.
y=(8-7.48)/2
y=.52/2
y=.26 answer.
proof:
7.74+.26=8
8=8
7.74*.26=2
2~2