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Two cars left a station in Bawku and were travelling to Tamale a distance of 135km away.
The second car left 30 minutes after the first car had left.
If the speed of the second car is 3/2 times as fast as the first car,
and the second car got to Tamale 45 minutes before the first car arrived,
calculated the speed of each car.
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Let v be the speed of the first car, in kilometers per hour.
Then the speed of the second car is , according to the problem.
The travel time of the first car is hours.
The travel time of the second car is hours, which is the same as .
The difference of the travel times is 30 + 45 minutes = 75 minutes = hours = hours.
So we write this "time equation"
- = .
Simplifying left side, we get
= .
Thus we find
v = = 9*4 = 36.
ANSWER. The speed of the first car is 36 km/h.
The speed of the second car is = 3*18 = 54 km/h.
Solved.