SOLUTION: One kind of hard candy sells for $0.89 per kilogram. Another sells for $1.10 per kilogram. How many kilograms of each kind will need to be used for 30 kilograms of a mixture to sel

Question 1178282: One kind of hard candy sells for $0.89 per kilogram. Another sells for $1.10 per kilogram. How many kilograms of each kind will need to be used for 30 kilograms of a mixture to sell for $0.96 per kilogram?
My answer is:
x = 20
30 - x = 30 - 20 = 10
Is my answer correct? If not, please provide the steps taken for solving this problem.
Thank you
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
https://www.algebra.com/my/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev
https://www.algebra.com/my/mixture-price-two-part-both-parts-unknown.lesson?content_action=show_dev

https://www.youtube.com/watch?v=-REjxT9KCzQ
https://www.youtube.com/watch?v=-REjxT9KCzQ
Two-Part Mixture, using just one variable

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.

Your answer has NOTHING in COMMON with the real solution.

On solving this kind of mixture problems, see the lessons
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
in this site.

Learn the subject from there.

        The solutions are presented there in all details, along and across, in deep and in height,
        step by step, starting from introducing the unknowns, showing the equation/equations,
        explaining their solutions; writing answers and checking the results.

Consider these lessons as your textbook, handbook, guidebook, tutorials and (free of charge) home teacher.

Happy learning (!)

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