SOLUTION: My rectangular cabbage patch has a total area of 115 sq. ft. Find its perimeter in terms of the width x.

Algebra.Com
Question 1115220: My rectangular cabbage patch has a total area of 115 sq. ft. Find its perimeter in terms of the width x.
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
My rectangular cabbage patch has a total area of 115 sq. ft. Find its perimeter in terms of the width x.
--------------
P = 2L + 2x --- L = Length
x*L = 115 --> L = 115/x
---
P = 2x + 230/x

RELATED QUESTIONS

if a rectangle has an area of 875 sq ft what is its length, perimeter,... (answered by Earlsdon)
My rectangular soccer field site has a length equal to one and a half times its width.... (answered by josgarithmetic)
My rectangular soccer field site has a length equal to twice its width. Find its area in... (answered by Earlsdon)
A rectangular vegetable patch has an area of 28 square meters and a perimeter of 22... (answered by ewatrrr)
A rectangle has a perimeter of 52ft and area of 120 sq ft. find the width of the... (answered by RedemptiveMath)
The area of a rectangular room is 399 sq. ft. Its length is 5.3 ft greater than its... (answered by TimothyLamb)
The area of a rectangular wall in a classroom is 216 sq ft. Its length is 3 ft shorter... (answered by ewatrrr)
A rectangle has a perimeter of 10 ft. Find a function that models its area A in terms of... (answered by josgarithmetic)
A rectangular family room has an area of 160 sq ft. THe length of the room is 6 ft... (answered by stanbon)