SOLUTION: Three persons A, B and C together have 875 loaves of bread. A has got 4 times as much as B but 25 loaves more than C. How many does C have?

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Question 1110811: Three persons A, B and C together have 875 loaves of bread. A has got 4 times as much as B but 25 loaves more than C. How many does C have?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28A%2BB%2BC=875%2CA%2FB=4%2CA=C%2B25%29

Solve the last two equations in terms of A, and substitute in the first equation; and first solve for A.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
A  + B +   C    = 875


4B + B + (B-25) = 875      <<<---=== One equation for one unknown B


6B - 25 = 875  ====>  6B = 875 + 25 = 900  ====> B = 900%2F6 = 150.


Answer.  B has 150 loaves.  A has  4*150 = 600 loaves.    C  has 150-25 = 125 loaves.


The lesson to learn from this solution: 

    This problem is for ONE unknown,

    and the way to solve it is to reduce it to one unknowns.