SOLUTION: Three persons A, B and C together have 875 loaves of bread. A has got 4 times as much as B but 25 loaves more than C. How many does C have?

Question 1110811: Three persons A, B and C together have 875 loaves of bread. A has got 4 times as much as B but 25 loaves more than C. How many does C have?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!

Solve the last two equations in terms of A, and substitute in the first equation; and first solve for A.
Answer by ikleyn(52781) (Show Source): You can put this solution on YOUR website!
.

A + B + C = 875 4B + B + (B-25) = 875 <<<---=== One equation for one unknown B 6B - 25 = 875 ====> 6B = 875 + 25 = 900 ====> B = = 150. Answer. B has 150 loaves. A has 4*150 = 600 loaves. C has 150-25 = 125 loaves.

The lesson to learn from this solution:

This problem is for ONE unknown, and the way to solve it is to reduce it to one unknowns.

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