SOLUTION: anita, cheri, miguel, and jake went bowling one night for fun they decided to pit the girls against the boys, with the highest score for each team winning. anita scored 18 less

Question 1106012: anita, cheri, miguel, and jake went bowling one night for fun they decided to pit the girls against the boys, with the highest score for each team winning.
anita scored 18 less than miguel, cheri's score was 16 less than twice anita's, cheri outscored jake by 21.
if the total score by all four kids was 529, what was the final scores of the match?

Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!

Let the scores be A, C, J, and M for Anita, Cheri, Jake, and Miguel, respectively.

The information as given is
(1) A = M-18
(2) C = 2A-16
(3) C = J+21

Rearrange the given information to express all four scores in terms on just one of them.

Equations (1) and (2) relate both C and M to A. Equation (3) relates J to C, so then equations (3) and (2) together let us relate J to A. So A should be the variable we use. Then
A = A
M = A+18 [from (1)]
C = 2A-16 [(2)]
J = 2A-37 [from (2) and (3)]

Then, since the sum of the scores was 529,

The individual scores were...
Anita = A = 94
Cheri = 2A-16 = 172
Jake = 2A-37 = 151
Miguel = A+18 = 112

CHECK:

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