SOLUTION: In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
My solution
Let X be the milk
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-> SOLUTION: In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
My solution
Let X be the milk
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Question 1086422: In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
My solution
Let X be the milk and Y be the water
x+y=126
x/y=5/2
y=2x/5
X+2x/5=126
7x=126*5
x=90
y=36
let water in this mixture be 3y
we have milk means y= 90
Water=90*3=270
Extra water added=270-36=234
answer is wrong please tell me where I have done the mistake Answer by ikleyn(52780) (Show Source):
You can put this solution on YOUR website! .
In the mixture of 126 kg of milk and water, milk and water are in the ratio 5:2 how much water must be added to the mixture to make this ratio 3:2.
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I will not follow your solution and will develop my own solution instead.
In the original mass of 126 kg of the mixture there are 7 (= 5 + 2) equal parts (masses).
Hence, the milk contents is = 5*18 = 90 kg,
and water contents is = 2*18 = 36 kg.
OK.
Next, the final mixture, having 90 kg of milk, must contain = 30*2 = 60 kg ow water to provide the ratio = .
Hence, 60 - 36 = 24 kg of water must be added to the original mixture to satisfy the problem requirements.
Answer. 24 kg of water must be added to the original mixture.
