SOLUTION: Identify if true of false proportions x^2+y^2=(x+y)^2

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Question 1085015: Identify if true of false proportions
x^2+y^2=(x+y)^2
Found 3 solutions by jim_thompson5910, ikleyn, Shin123:
Answer by jim_thompson5910(35256)   (Show Source):
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The equation as given is false. It is not true for all real numbers x and y.

The equation should be x^2+2xy+y^2=(x+y)^2 which is true for all real numbers x and y.

Answer by ikleyn(52776)   (Show Source):
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What is written in the post is not a proportion and has no any relation to proportions.

Answer by Shin123(626)   (Show Source):
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That equation is false. you need to add 2xy to the first side in order for it to be true.