SOLUTION: Edit:
Sorry for the post that have insufficient data, i checked again the problem and here it is:
y varies directly as the cube of x and square of z. If y = 5, if x = 2, & z =
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-> SOLUTION: Edit:
Sorry for the post that have insufficient data, i checked again the problem and here it is:
y varies directly as the cube of x and square of z. If y = 5, if x = 2, & z =
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Question 1014925: Edit:
Sorry for the post that have insufficient data, i checked again the problem and here it is:
y varies directly as the cube of x and square of z. If y = 5, if x = 2, & z = 3, what is y if x = 4 & z = 9?
thank you Answer by ikleyn(52786) (Show Source):
You can put this solution on YOUR website! .
Edit:
Sorry for the post that has insufficient data, i checked again the problem and here it is:
y varies directly as the cube of x and square of z. If y = 5 when x = 2, & z = 3, what is y if x = 4 & z = 9?
thank you
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O, this one is much better!
Answer. Then y = * * = 5*8*9 = 360.
