SOLUTION: two number have the ratio 3:4 if 5 is subtracted from each of the number the difference have ratio of 1:3 find the number

Question 1008688: two number have the ratio 3:4 if 5 is subtracted from each of the number the difference have ratio of 1:3 find the number
Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

let numbers be and
two number have the ratio or
....solve for
.........eq.1
if is subtracted from each of the number the difference have ratio of , we have
.........substitute from eq.1
...solve for , cross multiply first

go back to .........eq.1 substitute in for

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
two number have the ratio 3:4 if 5 is subtracted from each of the number the difference have ratio of 1:3 find the number
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x/y = 3/4
(x-5)/(y-5) = 1/3
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x = (3/4)y
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Substitute for "x" and solve for "y"::
((3/4)y -5)/(y-5) = 1/3
----
Cross-multiply::
3[(3/4)y-5] = y-5
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(9/4)y - 15 = y-5
(5/4)y = 10
y = 8
---
Solve for "x":
x = (3/4)y
x = (3/4)8 = 6
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Cheers,
Stan H.
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