SOLUTION: A baseball is thrown straight upward with an initial speed of 160 ft/sec. The number of feet s above the ground after t seconds is given by the equations = −16t^2 + 160t.(a)

Question 989291: A baseball is thrown straight upward with an initial speed of 160 ft/sec. The number of feet s above the ground after t seconds is given by the equations = −16t^2 + 160t.(a) When will the baseball be 256 feet above the ground? (Enter your answers as a comma-separated list.)
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

Here's the plot:

----------------
Find when

Divide both sides by

The baseball is 256 above ground at
2 sec ( on the way up ) and at
8 sec ( on the way down )

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SOLUTION: A baseball is thrown straight upward with an initial speed of 160 ft/sec. The number of feet s above the ground after t seconds is given by the equations = &#8722;16t^2 + 160t.(a)

SOLUTION: A baseball is thrown straight upward with an initial speed of 160 ft/sec. The number of feet s above the ground after t seconds is given by the equations = −16t^2 + 160t.(a)