SOLUTION: Find the area enclosed by the curve x=t^2

SOLUTION: Find the area enclosed by the curve x=t^2 - 2t, y=sqrt(t) and the y-axis.

Question 988657: Find the area enclosed by the curve x=t^2 - 2t, y=sqrt(t) and the y-axis.
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the area enclosed by the curve x=t^2 - 2t, y=sqrt(t) and the y-axis.
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Eliminate t
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x=t^2 - 2t
y=sqrt(t) --> t = y^2
x = y^4 - 2y^2
===============
The area is the same as y = x^4 - 2x^2 and the x-axis
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Find the 2 x-intercepts:
x = 0 is one.

-->
=================-
INT(x^4 - 2x^2) = x^5/5 - 2x^3/3
Area = ||
=~ 0.754247 sq units
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