SOLUTION: Let g(x) = x^4 - 6x^2 - x - 3 Find the maximum value and the minimum value of the 2nd derivative g" on the interval [-1,2] Please show the steps to solve. Thank you

Question 983091: Let g(x) = x^4 - 6x^2 - x - 3
Find the maximum value and the minimum value of the 2nd derivative g" on the interval [-1,2]
Please show the steps to solve.
Thank you
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
First find the second derivative.
First derivative,

Second derivative,

So the second derivative, in vertex form, has a vertex of (0,-1).
Since the multiplier is positive , it opens upwards so the value at the vertex is the minimum.
(,)
.
.
.
The maximum occurs at the endpoints specifically at since it is further away from the axis of symmetry .
(,)
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