SOLUTION: Charles rolled two six-sided die with sides numbered one through six. What is the probability that the total value of the numbers he rolled is less than or equal to nine? A. 90%

Question 982876: Charles rolled two six-sided die with sides numbered one through six. What is the probability that the total value of the numbers he rolled is less than or equal to nine?
A. 90%
B. 83%
C. 66%
D. 30%
E. 25%
Answer by reviewermath(1029) (Show Source): You can put this solution on YOUR website!
Charles rolled two six-sided die with sides numbered one through six. What is the probability that the total value of the numbers he rolled is less than or equal to nine?
A. 90%
B. 83%
C. 66%
D. 30%
E. 25%
Solution:
There are 6 � 6 = 36 possible outcomes when two six-sided die are rolled.
Let A = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1)(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3)}
n(A) = 30
P(A) = 30/36 = 5/6 or approximately 83%
Answer: B
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