SOLUTION: Find the equation of the tangent to the curve y= [4/(x^2)]+1 at the point where x=a. This tangent meets the axes at P(b,0) and Q(0,b). Find the value of a and of b.

Question 977879: Find the equation of the tangent to the curve y= [4/(x^2)]+1 at the point where x=a. This tangent meets the axes at P(b,0) and Q(0,b). Find the value of a and of b.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
THe slope of the tangent line is equal to the value of the derivative at that point.

So at ,

Also when ,

Using the point-slope form of a line to find the tangent line,

Multiply both sides by ,

.
.
When , ,

When ,,

So then,

Then,

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