SOLUTION: i have to find the center of a circle with an equation (x-2)squared+(y+3)squared=16

Question 97513: i have to find the center of a circle with an equation (x-2)squared+(y+3)squared=16
Found 2 solutions by mathslover, edjones:
Answer by mathslover(157) (Show Source): You can put this solution on YOUR website!

the general equation of a circle is
where (x1,y1) is the center of the circle and
r its radius
given
equation of the circle

rewriting this equation in the standard form

clearly the centre is (2,-3) and the radius 4

Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
(x-h)^2+(y-k)^2=r^2
(x-2)^2+(y+3)^2=16
h=2 k=-3 (2,-3)
Ed

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