SOLUTION: Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
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Question 965388: Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve on the interval from 0 to pi:2cos^2 x-3 sin x-3=0
AMP Parsing Error of [2(1-sin^2(x)-3sinx-3=0]: Invalid expression. Closing bracket expected =0 at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 187.
.
(2sinx+1)(sinx+1)=0
sinx=-1/2
no solution, not in domain
or
sinx=-1
no solution, not in domain
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