SOLUTION: I wasn't sure how to format logarithms, so I took a picture of the problem instead. http://imgur.com/QkovTSF

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Question 959275: I wasn't sure how to format logarithms, so I took a picture of the problem instead.
http://imgur.com/QkovTSF
Answer by josgarithmetic(39613) About Me  (Show Source):
You can put this solution on YOUR website!
The image shows equation, k%5E%28log%282%2C5%29%29=32

k%5E%28log%282%2C5%29%29=2%5E5
The form of each member seems to be the same. Base could be k=2, and the exponent could be log%282%2C5%29=5. Not seem right.


log%28k%5E%28log%282%2C5%29%29%29=log%282%2C2%5E5%29

log%282%2C5%29%2Alog%282%2Ck%29=5

log%282%2Ck%29=5%2Flog%282%2C5%29

Changing into exponential form,
k=2^(5/log(2,5)), in plain text; or try to render,
k=2%5E%285%2Flog%282%2C5%29%29.