SOLUTION: f(x) = 2x^3+3x^2-12x+4
Good Morning,
Please could you explain to me how to classify the stationary point(s) of the above function. I would then like to sketh its graph.
I
Algebra.Com
Question 943501: f(x) = 2x^3+3x^2-12x+4
Good Morning,
Please could you explain to me how to classify the stationary point(s) of the above function. I would then like to sketh its graph.
I would appreciate if you could explain it in full providing calculations.
Kind regards
David
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
f(x) = 2x^3+3x^2-12x+4
the graph of the equation looks like this,
there are 3 zero points on this graph
x = -3.4233
x = 0.37808
x = 1.5453
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