SOLUTION: the product of my three digits is 15. The sum of the first and third digit is 1 less than the second digit. The sum of the second and third digit is twice as large as the first dig

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Question 925243: the product of my three digits is 15. The sum of the first and third digit is 1 less than the second digit. The sum of the second and third digit is twice as large as the first digit. Who am I?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
the product of my three digits is 15, that is digits are 1,3,5
h (1st digit), t(2nd digit) u (3rd digit)
Question States...
h + u = t-1 0r t = h + u + 1 (t must be 5) 5 = 1 + 3 + 1
t + u = 2h 0r t = 2h-u 5 = 2*3 - 1 , u = 1 and h = 3
351 the number

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