SOLUTION: Find the equation for the asymtopes of the hyperbola x^2/9 - y^2/81 = 1

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Question 91513: Find the equation for the asymtopes of the hyperbola x^2/9 - y^2/81 = 1
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
x^2/9 - y^2/81 = 1
This is a horizontal hyperbola with center (0,0).
a = 3
b = 9
Box Points: (3,9), (-3,9), (3,-9), and (-3,-9)
m = +-3
y = m(x - x1) + y1
y = 3(x - 3) + 9 and y = -3(x + 3) + 9
y = 3x and y = -3x
graph%28300%2C300%2C-10%2C10%2C-30%2C30%2C3x%2C-3x%2C3%2Asqrt%28x%5E2+-+9%29%2C-3%2Asqrt%28x%5E2+-+9%29%29