SOLUTION: Find the equation for the asymtopes of the hyperbola x^2/9 - y^2/81 = 1

Algebra.Com
Question 91513: Find the equation for the asymtopes of the hyperbola x^2/9 - y^2/81 = 1
Answer by Nate(3500)   (Show Source): You can put this solution on YOUR website!
x^2/9 - y^2/81 = 1
This is a horizontal hyperbola with center (0,0).
a = 3
b = 9
Box Points: (3,9), (-3,9), (3,-9), and (-3,-9)
m = +-3
y = m(x - x1) + y1
y = 3(x - 3) + 9 and y = -3(x + 3) + 9
y = 3x and y = -3x

RELATED QUESTIONS

Find the vertices, foci, asymtopes for y. (y-2)^2/1 - (x-1)^2/4... (answered by lwsshak3)
Find the coordinate of the vertices and foci and the equation of the asymptotes for the... (answered by greenestamps,ikleyn)
Find the foci of the hyperbola. y^2/81-x^2/16=1 (answered by lynnlo)
hyperbola (x+2)^2 ________ 25 (x+2)^2 ________ 25 minus... (answered by Edwin McCravy)
Describe the vertical asymtopes and holes for the graph of y=(x-2)(x-2)/(x-2)(x+4)... (answered by richwmiller)
What equation would have the translation of y=4/x and has the asymtopes x=-7 ;... (answered by jim_thompson5910)
Find the coordinate of the vertices and foci and the equation of the asymptotes for the... (answered by Edwin McCravy,ikleyn)
Find the slopes of the asymptotes of a hyperbola with the following equation.... (answered by galactus)
Help stuck again. I have an hyperbola with the formula of 36x^2+144x+27-9y^2+36y=0 I need (answered by lwsshak3)