SOLUTION: An object is thrown with a velocity of v, in feet/second, from an initial height of s feet. The object's height at any time,t, in seconds, is given by h= -16t � + Vt+s.How long wo

Question 893279: An object is thrown with a velocity of v, in feet/second, from an initial height of s feet. The object's height at any time,t, in seconds, is given by h= -16t � + Vt+s.How long would it take an object thrown downward with an initial velocity of 25 ft/s from an initial height of 5280 ft to reach the ground? (Round your answer to the nearest tenth.)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
An object is thrown with a velocity of v, in feet/second, from an initial height of s feet. The object's height at any time,t, in seconds, is given by h= -16t � + Vt+s.How long would it take an object thrown downward with an initial velocity of 25 ft/s from an initial height of 5280 ft to reach the ground? (Round your answer to the nearest tenth.)
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h(t) = -16t^2 + Vt + s
h(t) = -16t^2 - 25t + 5280
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It reaches the ground when h(t) = 0
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h(t) = -16t^2 - 25t + 5280 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=338545 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: -18.9639437377964, 17.4014437377964. Here's your graph:

=================
t = 17.4 seconds

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