SOLUTION: solve the extended proportion x/9= 4/y= y/36 for x and y with x>0 and y>0

Question 887955: solve the extended proportion x/9= 4/y= y/36 for x and y with x>0 and y>0
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!

and
The first one is and the second one is ; so the first one is x=27/y=27/12, . Seems strange.
Maybe a mistake, maybe not. (I found the mistake, outlined in ).

Try differently. Split the three members from the original equation.

-
Now back to the first equation again.

-
This second solution seems better. You can search for any mistake I must have made in the first method.

CHECK THIS LAST SET OF RESULTS:

---Yes, looks good.
-
x=3, y=12
RELATED QUESTIONS
Solve for x and y if 2/x - 3/y = 2 and 4/x + 9/y + 1 =... (answered by KMST)

1+2+3+4+9+x+y+9+4+8+4-3+9-5+8-y+0+46464-46463=69+6.9-96 Solve for x and... (answered by MathLover1)

Solve the system for x and y y -2x = 0 x^2 + y^2 =... (answered by ewatrrr)

solve the equation for x in terms of y if {{{0 (answered by Fombitz)
solve by the addition method: (x/4) - (y-3) = -4 and (x/8) + (y/6) =... (answered by mananth)
Solve by the addition method: (x/4) � (y/3) = � 4 and (x/8) + (y/6) = 0 (answered by Fombitz)
1/x + 2/y - 4/z = 1 2/x + 3/y + 8/z = 0 -1/x + 9/y + 10/z = 5 then solve x, y and... (answered by Fombitz)
what are the non-permissible values for the rational expression x^2-4/y^2-4 a. y=0 and... (answered by bucky)
2x-y-x=0 solve for... (answered by checkley75)