SOLUTION: A bag contains 6 red marbles, 9 blue marbles, and 5 greem marbles. You withdraw 1 marble, replace it, and then withdraw another marble. What is the probability that you do NOT pi

Question 85871This question is from textbook Algebra concepts and applications
: A bag contains 6 red marbles, 9 blue marbles, and 5 greem marbles. You withdraw 1 marble, replace it, and then withdraw another marble. What is the probability that you do NOT pick two green marbles? This question is from textbook Algebra concepts and applications

Found 2 solutions by checkley75, rapaljer:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
20/20*15/20=300/400=75% SUCCESS THAT YOU DO NOT PICK 2 GREEN MARBLES.
THE FIRST OR THE SECOND PICK CAN BE ANY COLORED MARBLE. HOWEVER THE OTHER PICK CANNOT BE A GREEN MARBLE.
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
I'm not sure the other tutor's solution is correct. If you happen to have the correct answer to this, check it out and see who is correct!!

First, just to clarify the question, you are saying find the probability that that you do NOT get both marbles green. So, the probability of getting both marbles green would be
P(green)*P(green)

Now, probability that this does NOT happen =1-P(both green)

R^3 (R^2 Retired from SCC)
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