SOLUTION:
x + 3y = 13
2x – 3y = –19
(–2, 5)
(–2, 4)
(4, –2)
(5, –2)
Algebra.Com
Question 827671:
x + 3y = 13
2x – 3y = –19
(–2, 5)
(–2, 4)
(4, –2)
(5, –2)
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
x + 3y = 13
2x – 3y = –19
add the two equations.
3x = -6
divide each side by 3
x = -2
substitute -2 for x in x + 3y = 13
-2 + 3y = 13
add 2 to each side
3y = 15
divide by 3
y = 5
So x = -2 and y = 5 and the point is (-2,5)
RELATED QUESTIONS
linear algebra elimination method
13) 2/3x+2/5y=4/5
1/2x+2/3y=-1/2... (answered by Edwin McCravy)
3(2x+y)+5z=19
2(x-3y+4z)=23... (answered by josh's girl)
1. 4x+3y=1, x=1-y
2. 2x-y=6, -x+y=-1
3. 6x-y=3, 4x-2y=-2
4. 2x+3y=7, x=1-4y
5.... (answered by AnlytcPhil)
(-2x^2/3y)^4... (answered by Alan3354)
3y/4-y/2=5 (answered by edjones)
1. -2x^2 - y^2 + 24y + 76 = 0
x + 3y + 2 = 0
2. x^2 + y^2 + x +3y + 2 = 0
x - y =0
(answered by Fombitz)
How would I solve these systems?
1)x+5y=4
3x-7y=-10
2)-5x+3y=6
x-y=4
(answered by elima)
(-x^3y^4)^2 (answered by checkley71)
... (answered by london maths tutor)