SOLUTION: [ find an equation for the line through (2,6) and perpendicular to y = -5/4x + 1 ]

Question 823488: [ find an equation for the line through (2,6) and perpendicular to y = -5/4x + 1 ]
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
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perp lines have negative reciprocal slopes, so the perp slope = 4/5 = 0.8
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perp line contains (2,6)
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to solve the linear equation, copy and paste this (given point and perp slope):
2,6,0.8
into the "Point-Slope form: x1 y1 m" input box here: https://sooeet.com/math/linear-equation-solver.php
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x-intercept = (-5.5, 0)
y-intercept = (0, 4.4)
slope = 0.8
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answer:
the slope-intercept form:
y = 0.8x + 4.4
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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Solve systems of linear equations up to 6-equations 6-variables:
https://sooeet.com/math/system-of-linear-equations-solver.php
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