(x³+2x)(x²-x)| |x=2 Use u = x³+2x and v = x²-x = 3x²+2 = 2x-1 (x³+2x)(2x-1) + (x²-x)(3x²+2)| |x=2 (2³+2·2)(2·2-1) + (2²-2)(3·2²+2) (8+4)(4-1) + (4-2)(3·4+2) (12)(3) + (2)(12+2) 36 + (2)(14) 36 + 28 64 Edwin