SOLUTION: Nate rolls a fair, six-sided die 5 times. What is the probability that he will get at least 2 evens?

SOLUTION: Nate rolls a fair, six-sided die 5 times. What is the probability that he will get at least 2 evens?

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Question 781544: Nate rolls a fair, six-sided die 5 times. What is the probability that he will get at least 2 evens?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
nCr=n!/(r!(n-r)!)
5C0=.5^5=.031 none are even.
5C1=5*.5*.5^4=.156
.
.031+.156=.1875 Less than 2 evens occur.
1-.1875=0.8125 the probability that he will get at least 2 evens.
.
Ed
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