SOLUTION: PLEASE TUTORS,I NEED HELP FOR THIS PROBLEM.........A man is four times as old as his son. In 10 years time,the man's age will be twice that of his son.how old is the man and son at

Question 778380: PLEASE TUTORS,I NEED HELP FOR THIS PROBLEM.........A man is four times as old as his son. In 10 years time,the man's age will be twice that of his son.how old is the man and son at present?
Found 2 solutions by negative49, psbhowmick:
Answer by negative49(13) (Show Source): You can put this solution on YOUR website!
son's age : x
father's age : 4x
in 10 years
son's age: x + 10
father's age: 4x + 10
4x + 10 = 2 (x + 10)
4x + 10 = 2x + 20
2x = 10
x= 5
son's age: 5
father's age: 4(5) = 20
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
Let the age of the father be X and that of the son be Y.

X = 4Y _____ (1)

X+10 = 2(Y+10) _____ (2)

Substituting for X from (1) into (2)
4Y + 10 = 2Y + 20
2Y = 10
Y = 5

So, X = 4*5 = 20

So present age of father is 20 and that of son is 5.
It looks odd!!!
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