SOLUTION: the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial veloci

Question 760930: the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s. At what time is the bullet 5280 ft above the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
the height of a bullet fired straight up is given by h(t)=-16t^2+Vot+ho. Where Vo is the initial velocity and ho is the initial height. If the height is 20ft and the initial velocity is 2200 ft/s find the height of the bullet after 40s.
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h(t)=-16t^2+Vot+ho
h(t)=-16t^2 + 2200t + 20
Sub 40 for t to find h(40)
================================
At what time is the bullet 5280 ft above the ground?
h(t)=-16t^2 + 2200t + 20 = 5280
Solve for t

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