SOLUTION: the difference between the square of a number and twice the number is equal to 8. find both numbers that satisfy the condition above?

Question 760004: the difference between the square of a number and twice the number is equal to 8. find both numbers that satisfy the condition above?
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
the difference between the square of a number and twice the number = 8.
so n^2-2n=8
or n^2-2n-8=0
or n=[2+/-sqrt(2^2-4*1*-8)]/2*1=[2+/-sqrt(4+32)]/2=[2+/-sqrt(36)]/2
=[2+/-6]/2=[8 or -4}/2= 4 or -2
both numbers that satisfy the condition above are 4 or -2
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