SOLUTION: What's the vertex of the function f(x) =x^2-10x+20 and is it a a minimum or maximum

Question 745152: What's the vertex of the function f(x) =x^2-10x+20 and is it a a minimum or maximum
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Differentiate x^2 - 10x + 20 => 2x -10
=> make 2x - 10 =0 Therefore 2x = 10
x = 5
substitute values into the
differentiated form (2x - 10)
before and after x= 5
to establish whether negative or positive.
I used x= 4 and x = 6 and found that
it was minimum.
Substituting x = 5 into undifferentiated
form x^2 - 10x + 20 gave y = -5
So Vertex point (5, -5) Minimum
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