SOLUTION: Can you help me to solve this?
I know that the answer is 0
(x^2yz)/((x-y)(x-z)) +(y^2zx)/((y-z)(y-x))+(z^2xy)/((z-x)(z-y))
Algebra.Com
Question 739980: Can you help me to solve this?
I know that the answer is 0
(x^2yz)/((x-y)(x-z)) +(y^2zx)/((y-z)(y-x))+(z^2xy)/((z-x)(z-y))
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
--------
This is not solving, just simplifying.
=
Find a common denominator. (x-y)(x-z)(y-z) works
=
=
=
= 0
RELATED QUESTIONS
Can you help me solve this?
The answer is 0
I need the process!
(x^2yz)/((x-y)(x-z))... (answered by Alan3354)
How can I solve this?!
Please help me! The answer is 0
(x^2yz)/((x-y)(x-z))... (answered by Alan3354)
2zx^2y=18
x=1... (answered by rapaljer)
If X=logbase 24 12;y=logbase36 24;z=logbase48 36 then
xyz+1 = ?
a) 2xy b) 2zx c)... (answered by Boreal)
Solve it-:... (answered by ikleyn)
2zx^2y=18 where x=1, z=y
please help me solve this... (answered by sudhanshu_kmr)
(y + z)/x - z/x
(answered by Fombitz)
Please help me solve this equation.
x+y-z=0
2x-y+z=6... (answered by Alan3354)
can you help me solve this please thanks?
x+y-z=0
2x-y+z=3... (answered by solver91311)