SOLUTION: Find the maximum height of h=-16t^2+40t+5
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Question 728491: Find the maximum height of h=-16t^2+40t+5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the maximum height of h=-16t^2+40t+5
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Vertex occurs where t = -b/(2a) = -40/(2*-16) = 5/4
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Max height = h(5/4) = -16(5/4)^2+40(5/4)+5 = 30
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Cheers,
Stan H.
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