SOLUTION: Let f(x)= 2x^2-8x+7. What is the vertex -f the graph of f(x).

Question 726916: Let f(x)= 2x^2-8x+7. What is the vertex -f the graph of f(x).
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
-b/2a gives the x-coordinate of the vertex of the parabola with general equation

In this problem a=2 and b=-8 so the x-coordinate of the vertex is -(-8)/2*(2) = 2.

Plug 2 into the equation to find the y-coordinate of the vertex.

2(2)^2 -8*(2) + 7 = 2*4-16+7 = -1

The vertex is (2,-1)

Hope the solution helped. Sometimes you need more than a solution. Contact fcabanski@hotmail.com for online, private tutoring, or personalized problem solving (quick for groups of problems.)

RELATED QUESTIONS
Let f(x)=2x^2+8x+5. Rewrite the equation for f(x) in the form f(x)=(a(x-h)^2+k.The graph (answered by scott8148)

1. Let f(x) = 2x^2 − 8x − 7. What is the quadratic in vertex form that is y (answered by josgarithmetic)

Let f(x) = 2x^2 − 8x − 7. What is the quadratic in vertex form that is y = (answered by stanbon)

Find the vertex and than graph y= f(x)=2x^2+8x+16... (answered by Fombitz)

Let f(x) = 2x^2 − 8x − 7. Write the quadratic in vertex form (that is y... (answered by josgarithmetic)

1. Let f(x) = 2x^2 − 8x − 7. Write the quadratic in vertex form (that is y... (answered by stanbon)

Please help me solve this equation Let f(x) = 2x^2 − 8x − 7. (a) Write... (answered by josgarithmetic,MathTherapy)

what is the vertex of f(x)=x^2-8x-5 f(x)=-x^2+10x+6 (answered by htmentor)

Let f(x) = x^3 + 3x^2 + 4x - 7 and g(x) = 2x^4 - 8x^3 + 4x^2 - 1. What is the... (answered by ikleyn,math_tutor2020)