SOLUTION:
If the perimeter of a tennis court is 228 feet and the width is three feet shorter than half of the length, what are the dimensions of the tennis court?
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Question 720321:
If the perimeter of a tennis court is 228 feet and the width is three feet shorter than half of the length, what are the dimensions of the tennis court?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
P=2L+2W
W=L/2-3
228=2L+2(L/2-3)
228=2L+L-6
3L=228+6
3L=134
L=234/3
L=78 ANS. FOR THE LENGTH.
W=78/2-3=39-3=36 ANS. FOR THE WIDTH.
PROOF:
228=2*78+2*36
228=156+72
228=228
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